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6 October, 18:00

14. How many grams of NaCl are contained in 0.350 kg of a

0.238 m solution of sodium chloride?

83.3 g

0

4.87 g

4.87 g

O

13.9 g

o

1.43 g

+3
Answers (1)
  1. 6 October, 18:49
    0
    4.87g

    Explanation:

    Step 1:

    Data obtained from the question. This includes the following:

    Mass of solution = 0.35kg

    Molality = 0.238 m

    Mass of NaCl = ... ?

    Step 2:

    Determination of the number of mole of NaCl in the solution.

    Molality of a solution is simply defined as the mole of solute per unit kg of the solvent. It is given as:

    Molality = mol of solute / mass of solvent (kg)

    With the above formula, we calculate the mole of NaCl present in the solution as follow:

    Molality = mol of solute / mass of solvent (kg)

    0.238 = mol of NaCl / 0.35

    Cross multiply

    mol of NaCl = 0.238 x 0.35

    mol of NaCl = 0.0833 mol

    Step 3:

    Determination of the mass of NaCl in 0.0833 mol of NaCl.

    This is illustrated below:

    Number of mole NaCl = 0.0833 mol

    Molar Mass of NaCl = 23 + 35.5 = 58.5g/mol

    Mass of NaCl = ... ?

    Mass = number of mole x molar Mass

    Mass of NaCl = 0.0833 x 58.5

    Mass of NaCl = 4.87g

    Therefore, 4.87g of NaCl is contained in the solution.
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