A balloon containing helium gas expands from 230

mL to 860 mL as more helium is added. What was

the initial quantity of helium present if the

expanded balloon contains 3.8 x 10-4 mol,

assuming constant temperature and pressure?

Which of the variables are known?

Question

Karly Chan

11 July, 21:23

+3

Answers (1)

Know the Answer?

Jayda Donaldson · Answer 1

1.0 * 10^ (-4) mol

Explanation:

For gases:

n1/n2 = V1/V2

n1/3.8*10^ (-4) mol = 230 mL / 860 mL

n1 = 3.8*10^ (-4) * 230/860 = 1.0 * 10^ (-4) mol

A balloon containing helium gas expands from 230mL to 860 mL as more helium is added. What wasthe initial quantity of helium present if theexpanded balloon contains 3.8 x 10-4 mol,assuming constant temperature and pressure?Which of the variables are known?