How many joules are absorbed when 86.8 grams of water is heated from 40.0 degrees C to 86.0 degrees C?

a) 11,400 joules

b) 12,600 joules

c) 14,100 joules

d) 16,700 joules

The answer to your question is the letter d) 16700 joules

Explanation:

Data

mass = m = 86.8 g

temperature 1 = T1 = 40°C

temperature 2 = T2 = 86°C

heat capacity = 4.18 J/g°C

Process

1. - Write the formula to calculate Heat (Q)

Q = mC (T1 - T2)

2. - Substitution

Q = (86.8) (4.18) (86 - 40)

3. - Simplification

Q = (86.8) (4.18) (46)

4. - Result

Q = 16689.9 Joules ≈ 16700 joules