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20 June, 00:57

Describe the redox reaction. Check all that apply 2AI (s) + 3ZnCI2 (g) → 3Zn (s) + 2AICI3 (aq).

Aluminum atoms transfer electrons to chlorine atoms.

Zinc is reduced.

Zinc is the reducing agent.

The oxidation number of chlorine does not change.

Aluminum is oxidized.

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Answers (2)
  1. 20 June, 04:20
    0
    Answer: B, D, E
  2. 20 June, 04:42
    0
    Zinc is reduced.

    The oxidation number of chlorine does not change.

    Aluminum is oxidized.

    Explanation:

    For the reaction:

    2AI (s) + 3ZnCI₂ (g) → 3Zn (s) + 2AICI₃ (aq).

    For the elements in the reactants side:

    Al has (0) oxidation state and converted to (+3) oxidation state in the products (AlCl₃), which means Al is oxidized and it is the reducing agent.

    So, we can check that: Aluminum is oxidized.

    Zn has the oxidation state (+2) in the reactants side (ZnCl₂) and converted to (0) in the products side (Zn), which means that Zn is reduced and it is the oxidizing agent.

    So, we can check that: Zinc is reduced.

    and can not check: Zinc is the reducing agent.

    The oxidation state of Cl does not change, it is the same in both sides (-1).

    So, we can check: The oxidation number of chlorine does not change.

    and can not check: Aluminum atoms transfer electrons to chlorine atoms.

    So, the choices will be:

    Zinc is reduced.

    The oxidation number of chlorine does not change.

    Aluminum is oxidized.
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