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26 September, 07:39

5.00 L of air at 750 mmHg pressure was compressed into a 3.00 L steel cylinder. What is the final pressure? (round to significant figures)

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  1. 26 September, 10:07
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    P2 = 1250mmHg

    Explanation:

    V1 = 5.0L

    P1 = 750mmHg

    V2 = 3.0L

    P2 = ?

    According to Boyle's law, the volume of a fixed mass of gas is inversely proportional to its pressure provided that temperature remains constant.

    P = k/V k = P*V

    P1*V1 = P2*V2 = P3*V3 = ... = Pn*Vn

    P1 * V1 = P2 * V2

    Solve for P2

    P2 = (P1 * V1) / V2

    P2 = (750 * 5.0) / 3.0

    P2 = 3750 / 3

    P2 = 1250mmHg

    The final pressure of the gas is 1250mmHg
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