What is the charge of copper on the reactant side? What is the charge of the copper ions on the product side? Was the copper oxidized or reduced? By what number of electrons?

Equation: Cu + 4HNO3 - - > Cu (NO3) 2 + N204 + 2H20

1) The charge of copper on the reactant side is 0 (it is solid copper thus not charged).

2) The charge of the copper ions on the product side is 2 + (when ionized it is evident that Copper in Copper Nitrate is in its 2 + form)

3) Copper was Oxidized since its oxidation state increased from 0 as a reactant to + 2 as a product

4) The number of electrons transferred is 2 electrons. Since oxidation is the loss of electrons, then Copper lost 2 electrons.