at what temperature (inc) would the volume a gas be equal to 45.7L if the volume of gas was 33.9L at 12.4c

The answer to your question is T1 = 384.7 °K

Explanation:

Data

Volume 1 = V1 = 45.7 l

Temperature 1 = T1 = ?

Volume 2 = V2 = 33.9 l

Temperature 2 = T2 = 12.4°C

To solve this problem use Charles' law

V1/T1 = V2/T2

T1 = V1T2/V2

-Convert temperature to °K

T2 = 12.4 + 273 = 285.4°K

-Substitution

T1 = (45.7 x 285.4) / 33.9

-Simplification

T1 = 13042.8 / 33.9

-Result

T1 = 384.7 °K