Ask Question
2 November, 15:23

Write the equilibrium constant: Pb3 (PO4) 2 (s) = 3Pb2 + (aq) +

2PO2 (aq)

+3
Answers (1)
  1. 2 November, 16:17
    0
    Kc = [Pb²⁺]³.[PO₄³⁻]²

    Explanation:

    Let's consider the following reaction at equilibrium.

    Pb₃ (PO₄) ₂ (s) ⇄ 3 Pb²⁺ (aq) + 2 PO₄³⁻ (aq)

    The concentration equilibrium constant is the product of the concentrations of the products raised to their stoichiometric coefficients divided by the product of the concentrations of the reactants raised to their stoichiometric coefficients. It only includes gases and aqueous species.

    Kc = [Pb²⁺]³.[PO₄³⁻]²

    This equilibrium constant is known as the solubility product of Pb₃ (PO₄) ₂.
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Write the equilibrium constant: Pb3 (PO4) 2 (s) = 3Pb2 + (aq) + 2PO2 (aq) ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers