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26 May, 22:39

A 2.50L sample of nitrogen gas at a temperature of 308K has a pressure of 1.15atm. What is the new volume of the gas if the pressure is increased to 1.80atm and the temperature is decreased to 286K?

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  1. 27 May, 01:02
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    1.48L

    Explanation:

    From the question given, we obtained the following dа ta:

    V1 (initial volume) = 2.50L

    T1 (initial temperature) = 308K

    P1 (initial pressure) = 1.15atm

    P2 (final pressure) = 1.80atm

    T2 (final temperature) = 286K

    V2 (final volume) = ... ?

    Using the general gas equation P1V1/T1 = P2V2/T2, the final volume of the gas can obtain as follow:

    P1V1/T1 = P2V2/T2

    1.15 x 2.5/308 = 1.8 x V2/286

    Cross multiply to express in linear form:

    308 x 1.8 x V2 = 1.15 x 2.5 x 286

    Divide both side by 308 x 1.8

    V2 = (1.15 x 2.5 x 286) / (308 x 1.8)

    V2 = 1.48L

    Therefore, the new volume of the gas is 1.48L
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