For the reaction below, identify the excess reactant when 4.35 g of hydrogen reacts with 30.75 g of iodine to produce hydrogen iodide.

The excess reactant when 4.35 g of hydrogen reacts with 30.75g of hydrogen iodide is hydrogen

calculation

write the equation for the reaction

H2 (g) + I2 (g) → 2HI (g)

find the mole of each reactant

moles = mass/molar mass

moles of H2 = 4.35 g/2 g/mol = 2.175 moles

moles o I2 = 30.75 g / 254 g/mo=0.1211 moles

0.1211 moles of I2 reacted with 0.1211 moles of H2 but there are more moles of H2 there Hydrogen was in excess