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8 November, 16:05

How many moles of NaCl are present in 530 ml of a 1.52m NaCl solution

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  1. 8 November, 18:00
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    805.6 moles

    Explanation:

    Molarity = 1.52mL

    Volume = 530mL

    1.52 moles is present in 1mL,

    1mL = 0.001L

    1.52 moles = 0.001L

    X moles = 0.53L

    X = (1.52 * 0.53) / 0.001

    X = 805.6moles

    805.6moles is present in 530mL or 0.52L
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