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2 May, 14:27

What is the volume occupied by 0.103 mol of helium gas at a pressure of 0.95 atm and a temperature of 303 K?

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  1. 2 May, 18:10
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    The pressure of He gas, P = 0.95 atm

    Temperature, T = 303 K

    Gas constant, R = 0.0821 L. atm. K⁻¹mol⁻¹

    Number of moles of He gas, n = 0.103 mol

    According to an ideal gas equation, PV = nRT

    V = nRT/P

    = (0.103 mol) (0.0821 L. atm. K⁻¹mol⁻¹) (303 K) / 0.95 atm

    = 2.7 L

    Thus, the volume of the He gas is 2.7 L.
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