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26 July, 09:21

if the volume of a gas contracted from 648 mL to 0.15L, what was its final pressure if it started at a pressure of 485 kpa

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  1. 26 July, 10:16
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    2100 kPa

    Explanation:

    The temperature is constant, so the only variables are pressure and volume.

    We can use Boyle's Law.

    p₁V₁ = p₂V₂ Divide both sides of the equation by V₂

    p₂ = p₁ * V₁/V₂

    p₁ = 485 kPa; V₁ = 648 mL

    p₂ = ?; V₂ = 0.15 L = 150 mL Calculate p₂

    p₂ = 485 * 648/150

    p₂ = 2100 kPa
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