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22 July, 16:13

Having 23.26 g of NaOH and 18.73 g of HCl what will be the limiting reactant

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  1. 22 July, 19:49
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    NaOH + HCl = > NaCl + H2O

    1 mol of NaOH react with 1 mol of HCL

    The molecular mass of NaOH is 39.997

    The molecular mass of HCl is 36.46

    Moles of HCl

    =18.73/36.46

    =0.5137

    Mole of NaOH

    =23.26/39.997

    =0.5815

    moles of NaOH >moles of HCl

    so there are not enough HCl

    the answer is HCl
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