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7 February, 20:43

The neutralization sulfuric acid with sodium hydroxide yields

HSO4 (aq) + Na2OH (aa)

H2SO4 (aq) + NaOH (aq)

H2Na (1) + O2SO4 (aq)

H2O (l) + Na2SO4 (aq)

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Answers (1)
  1. 7 February, 23:00
    0
    H2O (l) + Na2SO4 (aq)

    Explanation:

    When sulphuric acid (H2SO4) is neutralized by sodium hydroxide (NaOH), the product formed are sodium sulphate (Na2SO4) and water (H2O). This is illustrated by the equation below:

    NaOH + H2SO4 - > Na2SO4 + H20

    Now we can balance the equation above as follow:

    There are 2 atoms of Na on the right side and 1atom on the left side. It can be balance by putting 2 in front of NaOH as shown below:

    2NaOH + H2SO4 - > Na2SO4 + H20

    Now we have a total of 4 atoms of H on the left side and 2 atoms on the right side. It can be balance by putting 2 in front of H2O as shown below:

    2NaOH + H2SO4 - > Na2SO4 + 2H20

    Now the equation is balanced.

    The product are Na2SO4 and H20
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