If I have 3.5 moles of C, and excess Fe2O3, how many moles of Fe can I produce?

2Fe2O3 + C → Fe + 300,

7 moles Fe

1.17 moles Fe

1.75 moles Fe

3.5 moles Fe

3.5 moles Fe

Explanation:

From the equation, Reaction of 2 moles of Fe₂O₃ with 1 mole of C produces 1 mole of Fe. When excess Fe₂O₃ is used, the only liming factor is C.

The ratio of amount of C used to the amount of Fe produced is 1:1

Therefore, if 3.5 moles of C are used, 3.5 moles of Fe are also produced.