Ask Question
25 April, 23:50

How many kilojoules are required to heat 0.500 g of water from 20.3 degrees Celcius to 29.7 degrees Celcius? How many Calories? Show your work and watch sig figs.

+4
Answers (1)
  1. 26 April, 00:44
    0
    Amount of heat = mass of water * specific heat (temperature change

    )

    = 0.500 g * 4.184 J / g-C (29.7 - 20.3) C

    = 19.6648 J

    = 0.0197 KJ

    And

    1 cal = 4.186798 J

    19.6648 J * 1 cal / 4.186798 J = 4.70 cal
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “How many kilojoules are required to heat 0.500 g of water from 20.3 degrees Celcius to 29.7 degrees Celcius? How many Calories? Show your ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers