100 ml of gaseous hydrocarbon consumes 300

ml of oxygen for the complete combustion.

The hydrocarbon is

a. C2H4

b. C2H2

C. C3H8

d. C2H6

a. C2H4.

Explanation:

Let's look at the balanced equation for C2H4.

C2H4 + 3O2 - -> 2CO2 + 2H2O

So 1 mole of this hydrocarbon reacts with 3 moles of oxygen and since 1 mole of one gas occupies the same volume as another gas, the volumes will be in the ratio 1:3. So this is the required hydrocarbon.

The answer would be a. C2H4 (ethylene)

1C2H4+3O2~>2CO2+2H2O