How many liters of water vapor are in 36.21 g?

45.02 L.

Explanation:

Firstly, we need to calculate the no. of moles of water vapor. n = mass / molar mass = (36.21 g) / (18.0 g/mol) = 2.01 mol. We can calculate the volume of knowing that 1.0 mole of a gas at STP occupies 22.4 L.

Using cross multiplication:

1.0 mole of CO occupies → 22.4 L.

2.01 mole of CO occupies →? L.

∴ The volume of water vapor in 36.21 g = (22.4 L) (2.01 mole) / (1.0 mole) = 45.02 L.