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3 February, 09:48

What volume of carbon monoxide will contain 3.02x10^23 molecules?

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  1. 3 February, 10:42
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    11.23 L.

    Explanation:

    Knowing that every one mole of a substance contains Avogadro's no. of molecules (NA = 6.022 x 10²³).

    Using cross multiplication:

    1.0 mole → 6.022 x 10²³ molecules.

    ? mole → 3.02 x 10²³ molecules.

    The no. of moles of CO = (3.02 x 10²³ molecules) (1.0 mole) / (6.022 x 10²³ molecules) = 0.5 mol. We can calculate the volume of knowing that 1.0 mole of a gas at STP occupies 22.4 L.

    Using cross multiplication:

    1.0 mole of CO occupies → 22.4 L.

    0.5 mole of CO occupies →? L.

    ∴ The volume of CO contain 3.02 x 10²³ molecules = (22.4 L) (0.5 mole) / (1.0 mole) = 11.23 L.
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