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31 May, 21:39

What volume would 3.00 moles of neon gas have at 295 K and 645 mmHg?

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  1. 31 May, 22:53
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    V = 85.619 L

    Explanation:

    To solve, we can use the ideal gas law equation, PV = nRT.

    P = pressure (645 mmHg)

    V = volume (?)

    n = amount of substance (3.00 mol)

    R = ideal gas constant (62.4 L mmHg/mole K)

    T = temperature (295K)

    Now we would plug in the appropriate numbers into the equation using the information given and solve for V.

    (645) (V) = (3.00) (62.4) (295)

    (V) = (3.00) (62.4) (295) / 645

    V = 85.619 L
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