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13 February, 21:49

How many moles of lithium are present in a sample that contains 2.45x10^87 formula units of Li2SO4?

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  1. 13 February, 23:55
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    The answer is: 8.14·10⁶³ moles of lithium are present.

    N (Li₂SO₄) = 2.45·10⁸⁷; number of formula units of lithium sulfate.

    n (Li₂SO₄) = N (Li₂SO₄) : Na.

    n (Li₂SO₄) = 2.45·10⁸⁷ : 6.022·10²³ 1/mol.

    n (Li₂SO₄) = 4.07·10⁶³ mol; amount of lithium sulfate

    In one molecule of lithium sulfate, there are two atoms of lithium.

    n (Li₂SO₄) : n (Li) = 1 : 2.

    n (Li) = 2 · 4.07·10⁶³ mol.

    n (Li) = 8.14·10⁶³ mol; amount of lithium atoms.
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