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29 June, 18:58

Potassium chlorate decomposes according to the following chemical equation:

2KCIO3 - - 2KCI + 3O2

If you start with 458g of KCIO3, what mass (g) of O2 will be produced?

83.71 L O2

179.39 L O2

687 L O2

67.2 L O2

+2
Answers (2)
  1. 29 June, 19:09
    0
    179.39 grams of O2 will be produced (option 2 is correct)

    Explanation:

    Step 1: Data given

    Mass of KClO3 = 458 grams

    Molar mass KClO3 = 122.55 g/mol

    Molar mass O2 = 32.0 g/mol

    Step 2: The balanced equation

    2KCIO3 → 2KCI + 3O2

    Step 3: Calculate moles KClO3

    Moles KClO3 = mass KClO3 / molar mass KClO3

    Moles KClO3 = 458 grams / 122.55 g/mol

    Moles KClO3 = 3.74 moles

    Step 4: Calculate moles of O2

    For 2 moles KClO3 we'll have 2 moles KCl and 3 moles O2

    For 3.74 moles we'll have 3/2 * 3.74 = 5.606 moles

    Step 5: Calculate mass O2

    Mass O2 = 5.606 moles * 32.0 g/mol

    Mass O2 = 179.39 grams

    179.39 grams of O2 will be produced (option 2 is correct)
  2. 29 June, 22:22
    0
    179.4 g of oyxgen will be produced.

    Option 2.

    Be careful because the units says L instead of g

    Explanation:

    Decomposition reaction:

    2KClO₃ → 2KCl + 3O₂

    2 moles of chlorate can decompose to 2 moles of chloride and 3 moles of oxygen.

    We convert the mass to moles, and then we make the rule of three:

    458 g / 122.55 g/mol = 3.74 moles of chlorate

    2 moles of chlorate can produce 3 moles of oxygen

    Then, 3.74 moles of chlorate may produce (3.74.3) / 2 = 5.60 moles of O₂

    We convert the moles to mass → 5.60 mol. 32 g / 1mol = 179.4 g
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