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9 March, 17:36

A 0.0997 mol sample of O2 has a pressure of 0.692 atm and a temperature of 333k. What is it's volume

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  1. 9 March, 21:12
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    The volume is 4,391 L

    Explanation:

    We use the formula PV=nRT:

    V = (nRT) / P

    V = (0,0997 mol x 0,082 l atm / K mol x 333K) / 0,692 atm

    V=4, 390980968 L
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