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25 December, 01:10

What is the molarity of a 500-ml solution containing 340 g of KI

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  1. 25 December, 03:20
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    Molarity (M) = 4.09

    (Written as 4.09M)

    Explanation:

    Molarity (M) = mol/L

    1st, calculate the number of moles of KI

    Molar mass of K = 39.098g per 1 mol

    Molar mass of I = 126.9g per 1 mol

    39.09+126.9 = 165.99g/mol

    Molar mass of KI = 165.99g/mol

    Since Molarity (M) is in units of mol/L,

    we need to change the given number of 340g of KI to moles.

    340g * 1mol/165.99g = 2.05mol KI

    Next, convert the given 500ml to Liters

    500ml * 1L/1000ml = 0.5L

    Lastly, plug these values into the eqaution for Molarity (mol/L)

    2.05mol/0.5L = 4.096 M

    Molarity (M) = 4.09
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