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9 August, 03:10

If you had 240 L container at 479 k and 300 kpa, what would the volume be if you changed the conditions to STP

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  1. 9 August, 06:23
    0
    The answer to your question is V2 = 434.7 l

    Explanation:

    Data

    Volume 1 = V1 = 240 l Volume 2 = ?

    Temperature 1 = T1 = 479°K Temperature 2 = T2 = 293°K

    Pressure 1 = P1 = 300 KPa Pressure 2 = P2 = 101.325 Kpa

    Process

    1. - Use the combined gas law to solve this problem

    P1V1/T1 = P2V2/t2

    -Solve for V2

    V2 = P1V1T2 / T1P2

    2. - Substitution

    V2 = (300) (240) (293) / (479) (101.325)

    3. - Simplification

    V2 = 21096000 / 48534.675

    4. - Result

    V2 = 434.7 l
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