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8 March, 10:38

When 435 J of heat is added to 3.4 g of olive oil at 21°C, the temperature increases to 98°C. What is the specific heat of olive oil?

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  1. 8 March, 11:37
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    The answer to your question is Cp = 1.66 J/g°C

    Explanation:

    Data

    Heat = Q = 435 J

    Mass = m = 3.4 g

    Temperature 1 = T1 = 21°C

    Temperature 2 = T2 = 98°C

    Specific heat = Cp = ?

    Process

    1. - Write the formula of heat

    Q = mCp (T2 - T1)

    -Solve for Cp

    Cp = Q / m (T2 - T1)

    2. - Substitution

    Cp = 435 / 3.4 (98 - 21)

    3. - Simplification

    Cp = 435 / 3.4 (77)

    Cp = 435 / 261.8

    4. - Result

    Cp = 1.66 J/g°C
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