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25 December, 05:52

How much heat is needed warm 65.34 g of water from 18.43 to 21.75

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  1. 25 December, 08:47
    0
    Given that

    Mass of water = 65.34 g

    Amount of heat = mass of water * specific heat (temperature change

    )

    = 65.34 g * 4.184 J / g-C (21.75-18.43) C

    = 907.63 J

    = 0.908 KJ

    And

    1 cal = 4.186798 J

    907.63 J * 1 cal / 4.186798 J = 216.78 cal

    Or0.218 kcal
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