The specific gravity of iron is 7.87, and the density of water at 4.00 ∘C is 1.00 g/cm3. You can use this information to find the density of iron.

Find the volume occupied by 7.00 g of iron.

Solution:

Density of iron (d) = ?

Specific gravity of iron=7.87

Density of water at 4°C=1g/cm^3

we have,

specific gravity = density of object/density of water at 4°C

or, 7.87=d/1

or, d=7.87g/cm^3

Again,

density=mass / volume

or, 7.87=7/V

or, V=7/7.87

or, V=0.88cm^3

therefore, volume occupied by iron is 0.88cm^3