The reaction of sodium peroxide and water produces sodium hydroxide and oxygen gas. The following balanced chemical equation represents the reaction.

2 Na^2O^2 (s) + 2 H^2O (l) → 4 NaOH (s) + O2 (g)

How many moles of sodium hydroxide are produced when 17.2 mol sodium peroxide reacts with water?

34.4 mol.

Explanation:

From the balanced equation:

2 Na₂O₂ (s) + 2 H₂O (l) → 4 NaOH (s) + O₂ (g),

It is clear that 2 moles of Na₂O₂ react with 2 moles of H₂O to produce 4 moles of NaOH and 1 mole of O₂.

Using cross multiplication:

2 moles of Na₂O₂ produce → 4 mole of NaOH.

17.2 moles of Na₂O₂ produce →? mole of NaOH.

∴ The no. of moles of NaOH produced = (4 mole) (17.2 mole) / (2 mole) = 34.4 mol.