Ask Question
4 February, 08:28

A man heats a balloon in the oven. If the balloon initially has a volume of 0.3 liters and a temperature of 25 0C, what will the volume of the balloon be after he heats it to a temperature of 275 0C?

+3
Answers (1)
  1. 4 February, 11:18
    0
    Answer: 0.55L

    Explanation:

    Given that,

    Original volume of balloon (V1) = 0.3L

    Original temperature of balloon (T1) = 25.0°C

    [Convert 25.0°C to Kelvin by adding 273

    25.0°C + 273 = 298K]

    New volume of balloon (V2) = ?

    New temperature of balloon (T2# = 275.0°C

    [Convert 25.0°C to Kelvin by adding 273

    275.0°C + 273 = 548K]

    Since volume and temperature are given while pressure is held constant, apply the formula for Charle's law

    V1/T1 = V2/T2

    0.3L/298K = V2/548K

    To get the value of V2, cross multiply

    0.3L x 548K = 298K x V2

    164.4L•K = 298K•V2

    Divide both sides by 298K

    164.4L•K / 298K = 298K•V2/298K

    0.55L = V2

    Thus, the new volume of the balloon would be 0.55 litres
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A man heats a balloon in the oven. If the balloon initially has a volume of 0.3 liters and a temperature of 25 0C, what will the volume of ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers