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15 September, 16:25

the pressure of a sample of helium in a 0.2 L container is 2.0atm. if the helium is compressed to a volume of 10.0 ml, what would be the pressure of the gas?

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  1. 15 September, 19:40
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    The pressure of the gas is 40atm

    Explanation:

    Given parameters:

    P₁ = 2.0atm

    V₁ = 0.2L

    V₂ = 10.0mL = 10 x10⁻³L = 0.01L

    P₂ = ?

    We apply Boyle's law to solve this kind of problem

    Boyle's law states that "the volume of a fixed mass of a gas varies inversely as the pressure changes if the temperature is constant".

    It is expressed as P₁V₁ = P₂V₂

    Making P₂ the subject of the formula gives:

    P₂ = P₁V₁/V₂

    Inserting the values of the parameters:

    P₂ = 2x0.2/0.01

    P₂ = 40atm
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