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14 September, 01:11

The volume of a gas at 27.0c and 0.200atm is 80.0 ml. what volume will the same gas sample occupy at STP?

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  1. 14 September, 03:36
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    V₂ = 14.56 mL.

    Explanation:

    We can use the general law of ideal gas: PV = nRT.

    where, P is the pressure of the gas in atm.

    V is the volume of the gas in L.

    n is the no. of moles of the gas in mol.

    R is the general gas constant,

    T is the temperature of the gas in K.

    If n is constant, and have different values of P, V and T:

    (P₁*V₁) / T₁ = (P₂ * V₂) / T₂

    Knowing that:

    V₁ = 80.0 mL, P₁ = 0.20 atm, T₁ = 27 °C + 273 = 300 K.

    V₂ = ? mL, P₂ (STP) = 1.0 atm, T₂ (STP) = 0 °C + 273 = 273 K.

    Applying in the above equation

    (P ₁ * V₁) / T₁ = (P₂ * V₂) / T₂

    (0.20 atm * 80.0 mL) / 300 K = (1.0 atm * V₂) / 273 K

    V₂ = (0.20 atm * 80.0 mL * 273 K) / (300 K * 1.0 atm)

    V₂ = 14.56 mL

    So, the answer is: V₂ = 14.56 mL.
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