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28 July, 21:32

Determine the concentration of a solution made by dissolving 1.40grams NaCL in enough water to make 30.0mL of solution.

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  1. 29 July, 00:33
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    Answer: 0.8M

    Explanation:

    Given that,

    Amount of moles of NaCl (n) = ?

    Mass of NaCl in grams = 1.40 g

    For molar mass of NaCl, use the molar masses:

    Sodium, Na = 23g;

    Chlorine, Cl = 35.5g

    NaCl = (23g + 35.5g)

    = 58.5g/mol

    Since, amount of moles = mass in grams / molar mass

    n = 1.40g / 58.5g/mol

    n = 0.024 mole

    Now, given that:

    Amount of moles of NaCl (n) = 0.024

    Volume of NaCl solution (v) = 30.0mL

    [Convert 30.0mL to liters

    If 1000 mL = 1L

    30.0mL = 30.0/1000 = 0.03L]

    Concentration of NaCl solution (c) = ?

    Since concentration (c) is obtained by dividing the amount of solute dissolved by the volume of solvent, hence

    c = n / v

    c = 0.024 mole / 0.03 L

    c = 0.8 M (0.8M means concentration is in moles per litres)

    Thus, the concentration of the solution is 0.8M
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