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31 January, 21:42

Elements x and y form 2 binary compounds. In the first 14.0 g of x combines with 3.0 g of y. In the second, 7.00 g of x combine with 4.50 g of y. The second compound has formula xy, what is the formula of the first one?

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  1. 31 January, 23:16
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    second compound

    Let molar mass of x is = X

    Let molar mass of y is = Y

    Moles of x in second compound = Mass / molar mass = 7 / X

    Moles of y in second compound = Mass / molar mass = 4.5 / Y

    For second compound

    7 / X : 4.5 / Y = 1:1

    Therefore

    X / Y = 7/4.5

    Y / X = 4.5 / 7

    The mass of x in first compound = 14g

    moles of x in first compound = 14/X

    Mass of y in first compound = 3

    moles of y in first compound = 3 / Y

    14 / X : 3 / Y = 14Y / 3X = 14 X 4.5 / 3 X 7 = 3 : 1

    Thus molar ratio in first compound = moles of x / Moles of y = 3:2

    Formula = x3y
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