At what celsius temperature does 0.750mol of an ideal gas occupy a volume of 35.9L at 114kPa

378.25°C

Explanation:

Given dа ta:

Number of moles of gas = 0.750 mol

Volume of gas = 35.9 L

Pressure of gas = 114 KPa (114/101 = 1.125 atm)

Temperature of gas = ?

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P = Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm. L / mol. K

T = temperature in kelvin

now we will put the values.

T = PV/nR

T = 1.125 atm * 35.9 L / 0.750 mol * 0.0821 atm. L / mol. K

T = 40.3875/0.062/K

T = 651.4 K

Kelvin to °C:

651.4 K - 273.15 = 378.25°C