Leon uses a pressure gauge to measure the air pressure in one of his car tires. The gauge shows that the pressure is 220 kilopascals. The temperature is 297 K, and the outdoor air is at standard pressure. If the tire contains 4.8 moles of air, what is the volume of the tire?

The volume of the tire is 37 L.

Leon is measuring the gauge pressure. The actual pressure is gauge pressure plus atmospheric pressure.

Standard atmospheric pressure is 1 bar = 100 kPa, so

p = (220 + 100) kPa = 320 kPa

pV = nRT

V = (nRT) / p = (4.8 mol * 8.314 kPa·L·K⁻¹mol⁻¹ * 297 K) / 320 kPa = 37 L