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24 November, 17:01

How many moles of glucose, C6H12O6, can be burned when 60.0 mol of oxygen is available? C6H12O6 (s) + 6O2 (g) → 6CO2 (g) + 6H2O (l)

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  1. 24 November, 18:02
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    60mol O2 * 1 mol C6H12O6 / 6 moles 02 = 10 moles of Glucose
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