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24 December, 15:54

The pressure of a sample of helium in a 1.0-L container is 0.857 atm. What is the new pressure if the sample is placed in a 0.5-L container? (Assume the temperature is constant.)

0.143 atm

0.429 atm

1.38 atm

1.71 atm

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  1. 24 December, 19:26
    0
    The new pressure is 1.714 atm

    calculation

    The new pressure is calculated using the Boyle's law formula

    that is P₁V₁ = P₂V₂

    where P₁=0.857 atm

    V₁ = 1.0 L

    P₂ = ?

    V₂ = 0.5 L

    make P2 the subject of the formula by diving both side by V₂

    P₂ = P₁V₁ / V₂

    P₂ = (0.857 atm x 1.0 L) / 0.5 L = 1.714 atm
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