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1 April, 01:00

What is the percent composition of muscovite mica if its chemical formula is (KF) 2 (Al2O3) 3 (SiO2) 6 (H2O)

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  1. 1 April, 02:58
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    Hello,

    To find the percentage composition of muscovite mica, we'll have to first find the molecular mass of the compound.

    Chemical formula = (KF) ₂ (Al₂O₃) ₃ (SiO₂) ₆ (H₂O)

    (KF) ₂ = 58.097 * 2 = 116.194g/mol

    (Al₂O₃) ₃ = 3 * 101.96 = 305.88g/mol

    (SiO₂) ₆ = 6 * 60.08 = 360.48g/mol

    H₂O = 18g/mol

    (KF) ₂ (Al₂O₃) ₃ (SiO₂) ₆ (H₂O) = 116.194 + 305.88 + 360.48 + 18 = 800.554g/mol

    Potassium = (78.18 / 800.554) * 100 = 9.765%

    Fluorine = (38 / 800.554) * 100 = 4.75%

    Aluminium = (162 / 800.554) * 100 = 20.23%

    Silicon = (168.48/800.554) * 100 = 21.04%

    Oxygen = (352/800.554) * 100 = 43.97%

    Hydrogen = (2 / 800.554) * 100 = 0.24%

    Muscovite mica is an aluminosilicate compound or a polysillicate compound found in rocks
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