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8 August, 06:18

How many grams of sodium hydroxide are present in 247.0 mL of a 0.300 M NaOH solution?

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  1. 8 August, 09:36
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    The grams of NaOH that are present in 247.0 ml of a 0.300M NaOH solution is 2.964 grams

    calculation

    Step 1: find moles of NaOH

    moles = molarity x volume in liters

    volume in liters = 247.0 / 1000 = 0.247 liters

    molarity = 0.300 M = 0.300 mol/l

    moles = 0.300 mol/l x 0.247 = 0.0741 moles

    step 2: find mass of NaOH

    mass = moles x molar mass

    The molar mass of NaOH = 23 + 1 + 16 = 40 g/mol

    mass=0.0741 moles x40 g/mol = 2.964 grams
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