A 159.0L sample of O2 gas is collected at 2.20 atm and 45C. If the temperature remains constant, what volume will the gas occupy if the pressure is decreased to 1.90 atm?

184.1 L

Explanation:the following data were obtained from the question:

V1 (initial volume) = 159.0L

P1 (initial pressure) = 2.20 atm

P2 (final pressure) = 1.90 atm

V2 (final volume) =.?

Since the temperature is constant, the gas is obeying Boyle's law. Using the Boyle's law equation P1V1 = P2V2, we can easily calculate the final volume of the gas as illustrated below:

P1V1 = P2V2

2.2 x 159 = 1.9 x V2

Divide both side by 1.9

V2 = (2.2 x 159) / 1.9

V2 = 184.1 L

Therefore, the final volume of the gas is 184.1 L