A balloon is filled with 12L of air at a pressure of 2 atm. What is the volume of ballon if the pressure is changed to 3 atm?

8L

Explanation:

Data obtained from the question include:

V1 (initial volume) = 12L

P1 (initial pressure) = 2atm

P2 (final pressure) = 3atm

V2 (final volume) = ?

Using Boyle's law equation P1V1 = P2V2, we can obtain the final volume of the balloon as follow:

P1V1 = P2V2

2 x 12 = 3 x V2

Divide both side by 3

V2 = (2 x 12) / 3

V2 = 8L

Therefore, the volume of the balloon when the pressure is changed to 3atm is 8L