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29 December, 20:44

A helium balloon can hold about 6.8 mol of the gas. Assuming the balloon is kept at room temperature (25°C) and had a maximum of 1.2L, what is the pressure inside teh balloon

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Answers (2)
  1. 29 December, 22:24
    0
    138.47atm

    Explanation:

    Data obtained from the question include:

    n (number of mole) = 6.8 mol

    T (temperature) = 25°C = 25 + 273 = 298K

    V (volume) = 1.2L

    R (gas constant) = 0.082atm. L/Kmol

    P (pressure) = ?

    Using the ideal gas equation PV = nRT, we can confidently calculate the pressure inside the balloon as shown below:

    PV = nRT

    P = nRT/V

    P = (6.8 x 0.082 x 298) / 1.2

    P = 138.47atm

    Therefore, the pressure inside the balloon is 138.47atm
  2. 29 December, 22:42
    0
    P = 138.6 atm or 1.4x10²

    Explanation:

    You will need to use PV=nRT to solve for P, pressure

    Where the R constant is 0.08206 L atm mol^-1 K^-1

    V is 1.2 L

    T is temperature in kelvin, 273.15+25 = 298.15

    n is 6.8 mol

    P*1.2=6.8*0.08206*298.15 - --> P*1.2=166.3700852 - --> P=166.3700852/1.2

    P=138.6 atm

    or 1.4x10²
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