Read the given equation.

Na2O2 + CO2 → Na2CO3 + O2

What volume of O2 gas is produced from 4.60 liters of CO2, assuming all values are measured at STP?

1.20 liters

2.30 liters

5.20 liters

9.20 liters

2.30 liters.

Explanation:

The balanced equation of the reaction is:

Na₂O₂ + CO₂ → Na₂CO₃ + 1/2O₂,

It is clear that 1.0 mole of Na₂O₂ reacts with 1.0 mole of CO₂ to produce 1.0 mole of Na₂CO₃ and 0.5 mole of O₂. The no. of moles of CO₂ in (4.60 L) reacted can be calculated from the relation: PV = nRT.

P is the pressure of the gas (P = 1.0 atm at STP),

V is the volume of the gas (V = 4.60 L),

R is the general gas constant (R = 0.082 L. atm/mol. K),

T is the temperature of the gas (T = 273.0 K at STP).

∴ n = PV/RT = (1.0 atm) (4.6 L) / (0.082 L. atm/mol. K) (273.0 K) = 0.205 mol.

Using cross multiplication:

1.0 mole of CO₂ produces → 0.5 mole of O₂, from the stichiometry.

0.205 mole of CO₂ produces →? mole of O₂.

The no. of moles of O₂ produced from 4.60 L of CO₂ = (0.5 mole) (0.205 mole) / (1.0 mole) = 0.103 mole. ∴ The volume of O₂ produced from 4.60 L of CO₂ = nRT/P = (0.103 mol) (0.082 L. atm/mol. K) (273.0 K) / (1.0 atm) = 2.30 liters.

B) 2.30 liters

Explanation:

I took the quiz and B was correct!