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10 October, 11:19

How many moles of H₂ would be required to produce 9.0 grams of water?

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  1. 10 October, 13:32
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    In 9.0 grams of water there are 0.11 mol of H₂.

    Explanation:

    The data we know is simple:

    1 mole (H₂O) 18 g (H₂O)

    - Taking this into account, a rule of 3 is made for 9.0 grams of water.

    1 mole (H₂O) 18 g (H₂O)

    X mole (H₂O) 9.0 g (H₂O)

    - We clear the X =

    X = 1 mol (H₂O) * 9 g (H₂O) / 18 g (H₂O)

    X = 0.5 mol (H₂O)

    - Now rule of 3 is done again but with the new dа ta:

    0.5 mol (H₂O) 9.0 g (H₂O)

    X mol (H₂) 2 g (H) (Which is the same as H₂)

    - Again we clear X:

    X = 2 g (H) * 0.5 mol (H₂O) / 9.0 g (H₂O)

    X = 0.11 gr (H₂)
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