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25 November, 03:13

Menthol, which is present in mentholated cough drops, is an organic compound

containing only C, H, and O. When a 0.2010-g sample is analyzed by combustion,

0.5658 g of CO2 and 0.2318 g of H2O are obtained. What is the empirical formula of

menthol?

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Answers (2)
  1. 25 November, 03:23
    0
    The empirical formula is C10H20O

    Explanation:

    Step 1: Data given

    Mass of the sample = 0.2010 grams

    Mass of CO2 = 0.5658 grams

    Molar mass CO2 = 44.01 g/mol

    Mass of H2O = 0.2318 grams

    Molar mass H2O = 18.02 g/mol

    Atomic mass C = 12.01 g/mol

    Atomic mass O = 16.0 g/mol

    Atomic mass H = 1.01 g/mol

    Step 2: calculate moles CO2

    Moles CO2 = 0.5658 gram / 44.01 g/mol

    Moles CO2 = 0.01286 moles

    Step 3: Calculate moles C

    For 1 mol CO2 we have 1 mol C

    For 0.01286 moles CO2 we have 0.01286 moles C

    Step 4: Calculate mass C

    MAss C = 0.01286 moles * 12.01 g/mol

    Mass C = 0.1544 grams

    Step 5: Calculate moles H2O

    Moles H2O = 0.2318 grams / 18.02 g/mol

    Moles H2O = 0.01286 moles

    Step 6: Calculate moles H

    For 1 mol H2O we have 2 moles H

    For 0.01286 moles H2O we have 2*0.01286 = 0.02572 moles H

    Step 7: Calculate mass H

    Mass H = 0.02572 moles * 1.01 g/mol

    Mass H = 0.0260 grams

    Step8: Calculate mass O

    Mass O = 0.2010 - 0.1544 - 0.0260

    Mass O = 0.0206 grams

    Step 9: Calculate moles O

    Moles O = 0.0206 grams / 16.0 g/mol

    Moles O = 0.00129 moles

    Step 10: Calculate the mol ratio

    We divide by the smallest amount of moles

    C: 0.01286 moles / 0.00129 moles = 10

    H: 0.02572 moles / 0.00129 moles = 20

    O: 0.00129 moles / 0.00129 moles = 1

    The empirical formula is C10H20O
  2. 25 November, 05:39
    0
    Answer: guvf6fr688ybuun
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