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14 May, 10:37

A 3.75 g sample of limestone, CaCO3, contains 1.80 g of oxygen and 0.450 g of carbon. What mass of calcium is present in the sample?

a. 1.00 g

b. 1.25 g

c. 1.50 g

d. 1.75 g

e. 2.00 g

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Answers (1)
  1. 14 May, 14:06
    0
    The mass of calcium in this sample is 1.50 grams (option c is correct)

    Explanation:

    Step 1: data given

    Mass of CaCO3 = 1.80 grams

    Molar mass CaCO3 = 100.09 g/mol

    Mass of oxygen = 1.80 grams

    Mass of carbon = 0.450 grams

    Step 2: Calculate mass %

    Mass % oxygen = (1.80 grams / 3.75 grams) * 100 %

    Mass % oxygen = 48.0 %

    Mass % carbon = (0.450 grams / 3.75 grams) * 100 %

    Mass % carbon = 12.0 %

    Step 3: Calculate mass % calcium

    Mass % Ca = 100 % - 48.0 % - 12.0 %

    Mass % Ca = 40.0 %

    Step 4: Calculate mass Calcium

    Mass Calcium = 3.75 grams * 0.40

    Mass Calcium = 1.50 grams

    The mass of calcium in this sample is 1.50 grams (option c is correct)
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