The balanced equation for the reaction of nitrogen gas and fluorine gas is

N2 (g) + 3 F2 (g) → 2 NF3 (g)

What is the limiting reactant if 25 N2 molecules are allowed to react with 75 F2 molecules?

a. N2

b. F2

c. NF3

d. There is no limiting reactant: the reactants are present in stoichiometrically equivalent amounts

e. More information is needed to solve this problem

We don't have a limiting reactant.

The reactants are present in stoichiometrically equivalent amounts.

Option D is correct

Explanation:

Step 1: Data given

Molecules N2 = 25 molecules

Molecules F2 = 75 molecules

Number of Avogadro = 6.02 * 10^23 / moles

Step 2: Calculate moles N2

Moles N2 = molecules N2 / number of Avogadro

Moles N2 = 25 / 6.02 * 10^23

Moles N2 = 4.15 * 10^-23 moles

Step 3: Calculate moles F2

Moles F2 = 75 molecules / 6.02 * 10^23

Moles F2 = 1.25 * 10^-22 moles

Step 4: Calculate limiting reactant

For 1 mol N2 we need 3 moles F2 to produce 2 moles NF3

For 4.15 * 10^-23 moles N2 we need 1.25 * 10^-22 moles F2

OR

For 25 molecules N2 we need 75 molecules F2

Both reactants will completely react.

This means we don't have a limiting reactant.

The reactants are present in stoichiometrically equivalent amounts.

Option D is correct