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9 October, 00:51

If a gas in a closed container is pressurized from 14.9 atm to 16.5 atm and its original temperature was 33.1 °C, what would the final temperature of the gas be?

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  1. 9 October, 01:48
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    Answer: 339K

    Explanation:

    Initial pressure P1 = 14.9 atm

    Final pressure P2 = 16.5 atm

    Original temperature T1 = 33.1 °C

    Convert Celsius to Kelvin

    (33.1°C + 273 = 306.1K)

    Final temperature T2 = ?

    Apply the formula for Pressure's law

    P1/T1. = P2/T2

    14.9atm/306.1K = 16.5atm / T2

    To get T2, cross multiply

    14.9 x T2 = 16.5 x 306.1

    14.9T2 = 5050.65

    T2 = (5050.65/14.9)

    T2 = 339K

    Thus, the final temperature of the gas would be 339K
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